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Dental school · D2 Oral Radiology · Review sheet · Free

X-Ray Production & Exposure Factors

Chapter: X-Ray Physics and Image Production

Updated 2026-10-20

The x-ray tube

  • Cathode: heated tungsten filament releases electrons (thermionic emission); a molybdenum focusing cup aims them at the target.
  • Anode: tungsten target set in copper (which conducts heat away). The focal spot is the area struck; a smaller effective focal spot gives a sharper image (line focus principle).
  • Over 99% of the electrons' energy becomes heat; under 1% becomes x-rays.
  • Bremsstrahlung (braking) radiation makes most of the beam, with a continuous energy spectrum; characteristic radiation (electron ejected from an inner shell of tungsten) is a small share.
  • Aluminum filtration removes low-energy photons that would only add skin dose: at least 1.5 mm Al at or below 70 kVp and 2.5 mm above 70 kVp. Collimation limits beam size: round beam no more than 2.75 in (7 cm) at the skin; rectangular collimation cuts patient dose substantially.

Exposure factors

ControlChangesImage effect
mA (tube current)Number of electrons, so number of photons (quantity)Higher mA → darker image (more density); no change in contrast
Exposure timeNumber of photonsLonger → darker; mA × time = mAs
kVp (tube voltage)Photon energy and penetration (quality), also some quantityHigher kVp → darker and LOWER contrast (long gray scale); lower kVp → higher contrast (short scale)
Source-to-receptor distanceIntensity follows the inverse square lawLonger distance → lighter image unless exposure is increased; less magnification and sharper image
  • Inverse square law: intensity ∝ 1/distance². Moving from 8 in to 16 in cuts intensity to ¼, so exposure must be multiplied by 4; from 8 in to 12 in needs (12 ÷ 8)² = 2.25 times the exposure.
  • Sharpness improves with a small focal spot, a long source-object distance, a short object-receptor distance and no motion.

Photon interactions in tissue

InteractionShare (approximate)Meaning
Coherent (Thomson) scatterAbout 7–8%Photon changes direction without ionization; minor fog
Photoelectric absorptionAbout 30%Photon fully absorbed; creates image contrast and most patient absorbed dose; more likely in dense, high atomic number tissue
Compton scatterAbout 60%Photon loses part of its energy and scatters; main source of image fog and of scatter exposure to the operator
No interactionRemainder of the beamPasses through to form the image

⚠️ Common traps

  • Saying kVp only changes darkness: it also changes contrast.
  • Saying mA changes beam energy: mA changes quantity, kVp changes quality.
  • Doubling exposure (instead of quadrupling) when the distance is doubled.
  • Assigning patient dose mainly to Compton scatter: photoelectric absorption contributes most of the patient's absorbed dose.

Mini-quiz

Pick an answer to see right away whether it is correct and why.

  1. Which change produces a radiograph with LOWER contrast (longer gray scale)?
  2. The source-to-receptor distance is increased from 8 in to 16 in. To keep the same image density, exposure time must be:
  3. Most x-ray photons produced in a dental tube come from:
  4. What is the purpose of aluminum filtration?
  5. Which interaction is the main cause of scatter exposure to the operator?
0 of 5 answered

Answer key: 1 B · 2 D · 3 B · 4 A · 5 D