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Genetics & Heredity

Chapter: Genetics and Heredity

Updated 2026-10-19

Mendelian ratios

  • Monohybrid Aa × Aa: genotypes 1 AA : 2 Aa : 1 aa; phenotypes 3 : 1.
  • Dihybrid AaBb × AaBb (unlinked): 9 : 3 : 3 : 1.
  • Test cross (unknown × homozygous recessive): Aa × aa gives 1 : 1; AaBb × aabb gives 1 : 1 : 1 : 1.
  • Product rule (independent events, 'and'): multiply. Sum rule (mutually exclusive, 'or'): add.
  • For multi-gene crosses, solve each gene separately and multiply: P(aabb) from AaBb × AaBb = ¼ × ¼ = 1/16.

Beyond simple dominance

PatternFeatureExample
Incomplete dominanceHeterozygote is intermediate; phenotype ratio 1 : 2 : 1Pink snapdragons
CodominanceBoth alleles fully expressedAB blood type
Multiple allelesMore than two alleles in the populationABO (Iᴬ, Iᴮ, i)
EpistasisOne gene masks another; modified dihybrid ratios such as 9 : 3 : 4Labrador coat color
PolygenicMany genes add up; continuous variationHeight, skin color
PleiotropyOne gene affects many traitsMarfan syndrome
MitochondrialPassed from mother to all childrenSome myopathies

Pedigree clues

InheritanceClues
Autosomal dominantEvery generation; affected child has an affected parent; males and females equal
Autosomal recessiveSkips generations; unaffected carrier parents; consanguinity raises risk
X-linked recessiveMostly males; passed through carrier mothers; never father → son
X-linked dominantAffected father → ALL daughters and no sons
MitochondrialAffected mother → all children; affected father → none

Linkage and populations

  • Recombination frequency = recombinant offspring ÷ total offspring; 1% = 1 map unit (centimorgan). Maximum is 50% (looks unlinked).
  • Hardy–Weinberg: p + q = 1 and p² + 2pq + q² = 1. Requires a large population, random mating, no mutation, no migration (gene flow) and no selection.
  • Start from the recessive phenotype frequency: q = √(q²). Carriers = 2pq.
  • Common aneuploidies: Down syndrome (trisomy 21), Turner (45,X), Klinefelter (47,XXY).

⚠️ Common traps

  • Using the 9 : 3 : 3 : 1 ratio for linked genes.
  • Taking q directly from the affected fraction without the square root.
  • Allowing father-to-son transmission in X-linked traits.
  • Adding probabilities for independent events instead of multiplying.

Mini-quiz

Pick an answer to see right away whether it is correct and why.

  1. Two AaBb individuals (unlinked genes) are crossed. What fraction of offspring is aabb?
  2. In a population at Hardy–Weinberg equilibrium, 9% show a recessive trait. What fraction are carriers?
  3. An affected father has only affected daughters and only unaffected sons, across several families. Which inheritance fits best?
  4. Two genes show 12% recombinant offspring. How far apart are they?
  5. Parents with blood types A (Iᴬi) and B (Iᴮi) have a child. What is the probability the child is type O?
0 of 5 answered

Answer key: 1 C · 2 C · 3 C · 4 B · 5 B